You are working at a construction site and need to use a cable to lift a 7.00 kg package. The package starts at rest on the ground, and you need to lift it to a height of 20.0 m in 7.30 s. Assume constant acceleration.  What acceleration is required?

To find the required acceleration, you can use the equation of motion for constant acceleration:

h = vit + 0.5a*t^2,

where h is the height, vi is the initial velocity (0 m/s), t is the time, and a is the acceleration.

Rearranging the equation for acceleration:

a = 2 * (h - vi * t) / t^2 = 2 * (20.0 m - 0 * 7.30 s) / (7.30 s)^2 = 6.09 m/s^2

Therefore, the required acceleration is 6.09 m/s^2.


(Which is wrong -- the equation is correct, but the correct number is 0.751 m/s^2.)